Tengo una consulta. Necesito ejecutarla como una consulta dinámica para generar un nombre de columna significativo. Como ejemplo, si ejecuto la consulta directamente, devuelve datos correctamente. Sin embargo, si uso por debajo de código, se muestra:¿ejecutó error porque el nombre no es un identificador válido?
The name '
SELECT (CASE WHEN A.Domain IS NOT NULL THEN A.Domain ELSE B.Domain END) AS [Domain],
(CASE WHEN A.Email IS NOT NULL THEN A.Email ELSE B.Email END) AS [Email],
A.[Sender Size] AS [Sender Size 1], A.[Sender Count] AS [Sender Count 1],
A.[Receiver Size] AS [Receiver Size 1], A.[Receiver Count] AS [Receiver Count 1],
A.[Sender Size 2] AS [Sender Size 2], A.[Sender Count 2] AS [Sender Count 2],
A.[Receiver Size 2] AS [Receiver Size 2], A.[Receiver Count 2] AS [Receiver Count 2],
B.SenderSize AS [Sender Size Average], B.SenderCount AS [Sender Count Average],
B.ReceiverSize AS [Receiv' is not a valid identifier.
A continuación es el código:
DECLARE @query NVARCHAR(4000)
SET @query = N'SELECT *
FROM
(
SELECT (CASE WHEN A.Domain IS NOT NULL THEN A.Domain ELSE B.Domain END) AS [Domain],
(CASE WHEN A.Email IS NOT NULL THEN A.Email ELSE B.Email END) AS [Email],
A.[Sender Size] AS [Sender Size 1], A.[Sender Count] AS [Sender Count 1],
A.[Receiver Size] AS [Receiver Size 1], A.[Receiver Count] AS [Receiver Count 1],
A.[Sender Size 2] AS [Sender Size 2], A.[Sender Count 2] AS [Sender Count 2],
A.[Receiver Size 2] AS [Receiver Size 2], A.[Receiver Count 2] AS [Receiver Count 2],
B.SenderSize AS [Sender Size Average], B.SenderCount AS [Sender Count Average],
B.ReceiverSize AS [Receiver Size Average], B.ReceiverCount AS [Receiver Count Average]
FROM
(
SELECT (CASE WHEN tf.Domain IS NOT NULL THEN tf.Domain ELSE tf2.Domain END) AS Domain,
(CASE WHEN tf.Email IS NOT NULL THEN tf.Email ELSE tf2.Email END) AS Email,
ISNULL(tf.SenderSize,0) AS [Sender Size] , ISNULL(tf.SenderCount,0) AS [Sender Count], ISNULL(tf.ReceiverSize,0) AS [Receiver Size], ISNULL(tf.ReceiverCount,0) AS [Receiver Count],
ISNULL(tf2.SenderSize,0) AS [Sender Size 2], ISNULL(tf2.SenderCount,0) AS [Sender Count 2], ISNULL(tf2.ReceiverSize,0) AS [Receiver Size 2], ISNULL(tf2.ReceiverCount,0) AS [Receiver Count 2]
FROM #TrafficFinal tf FULL JOIN #TrafficFinal2 tf2 ON (tf.Email = tf2.Email AND tf.Domain = tf2.Domain)
) A FULL JOIN #TrafficFinal3 B ON (A.Email = B.Email AND A.Domain = B.Domain)
) C
ORDER BY Domain, Email';
PRINT @query;
-- run it
exec @query;
¿Es debido a la plena unirse?
perdón por eso. Me tomó un tiempo descubrir que se puede hacer clic en el símbolo de verificación. – urlreader