MySQL - ¿Cómo obtengo SUMA de un COUNT de un campo?

Question

Estoy usando la siguiente declaración y obtengo casi todo lo que necesito. Además, me gustaría obtener la SUMA de todos los resultados row_total.

SELECT c.id AS campaign_id, c.amount AS campaign_amount, c.warning_trigger, 
COUNT(cc.id) as code_count, DATEDIFF(c.end_date, CURDATE()) as days_remain, 
SUM(c.amount) as row_total 
FROM campaigns c 
JOIN campaign_codes cc 
LEFT JOIN partners p on p.id = 4 
WHERE c.partner_id = 4 AND cc.status = 0 AND c.id = cc.campaign_id 
GROUP BY c.id 
ORDER BY campaign_amount ASC 

Y aquí es un resultado ejemplo, con la última columna es la columna quiero añadir juntos:

1 10.00 30 992 24 9920.00 
    3 25.00 30 995 290 24875.00 
    16 50.00 30 988 335 49400.00 
    17 100.00 30 1000 335 100000.00 

Answer 1

para obtener la suma en ejecución:

SELECT c.id AS campaign_id, c.amount AS campaign_amount, c.warning_trigger, 
     COUNT(cc.id) as code_count, DATEDIFF(c.end_date, CURDATE()) as days_remain, 
     SUM(c.amount) as row_total, @r := @r + SUM(c.amount) AS running_sum 
FROM (
     SELECT @r := 0 
     ) vars, 
     campaign c, … 

Para obtener el total general (y todos los otros agregados) como un registro adicional:

SELECT * 
FROM (
     SELECT c.id AS campaign_id, c.amount AS campaign_amount, c.warning_trigger, 
       COUNT(cc.id) as code_count, DATEDIFF(c.end_date, CURDATE()) as days_remain, 
       SUM(c.amount) as row_total 
     FROM campaign c, … 
     GROUP BY 
       c.id WITH ROLLUP 
     ) q 
ORDER BY 
     campaign_amount ASC 

para obtener la suma total en una campo adicional:

 SELECT c.id AS campaign_id, c.amount AS campaign_amount, c.warning_trigger, 
       COUNT(cc.id) as code_count, DATEDIFF(c.end_date, CURDATE()) as days_remain, 
       SUM(c.amount) as row_total, 
       (
       SELECT SUM(c.amount) 
       FROM campaign c, … 
       -- the same but without the GROUP BY and ORDER BY clauses. 
       ) 
     FROM campaign c, … 
     GROUP BY 
       c.id 
     ORDER BY 
       campaign_amount ASC 

Answer 2

encapsular su consulta como:

SELECT SUM([row_total]) FROM (
Your query 
) Source 

A partir de los comentarios de abajo, usted podría intentar ...

Your Query 
UNION ALL 
SELECT '', '', '', '', '', SUM([row_total]) FROM (
Your query 
) Source 

La unión de todos le permitirá agregar una fila adicional al conjunto de resultados que le dará una 'fila total'. Puede cambiar los campos vacíos (las comillas simples) para que coincidan con sus tipos de datos o asignarles valores especiales que representarán su fila total.

Answer 3

SELECT TB.campaign_id, TB.campaign_amount, TB.warning_trigger, TB.code_count, TB.days_remain, TB.row_total, SUM(TB.row_total) GlobalTotal FROM (SELECT c.id AS campaign_id, c.amount AS campaign_amount, c.warning_trigger, 
COUNT(cc.id) as code_count, DATEDIFF(c.end_date, CURDATE()) as days_remain, 
SUM(c.amount) as row_total 
FROM campaigns c 
JOIN campaign_codes cc 
LEFT JOIN partners p on p.id = 4 
WHERE c.partner_id = 4 AND cc.status = 0 AND c.id = cc.campaign_id 
GROUP BY c.id 
ORDER BY campaign_amount ASC) TB 
GROUP BY TB.campaign_id, TB.campaign_amount, TB.warning_trigger, TB.code_count, TB.days_remain, TB.row_total