Django: cómo mostrar errores de formulario para cada objeto de modelo en un formset en línea

Question

Tengo un modelo de autor y un modelo de libros. Un usuario puede modificar las propiedades de todos los libros de un autor determinado. Quiero poder mostrar los errores para cada libro individual en lugar de tener todos los errores enumerados en la parte superior. ¿Cómo puedo hacer esto?

MODELOS

from django.db import models 
from django.forms import ModelForm, Textarea 
from django import forms 

class Author(models.Model): 
    fname = models.CharField(max_length=100) 
    lname = models.CharField(max_length=100) 
    def fullname(self): 
     return '%s %s' % (self.fname, self.lname) 
    fullname = property(fullname) 
    def __unicode__(self): 
     return self.fullname 

class Books(models.Model): 
    author = models.ForeignKey(Author) 
    title = models.CharField(max_length=50) 
    publisher = models.CharField(max_length=50) 
    edition = models.CharField(max_length=50) 
    comment = models.TextField() 
    def __unicode__(self): 
     return self.title 

VER

def author_books_edit(request, author_id): 
    a = get_object_or_404(Author, pk=author_id) 
    authorsbooks = a.books_set.all() 
    bookformset = inlineformset_factory(Author, Books, can_delete=True, can_order=True, exclude=('company',), extra=1) 
    formset = bookformset(instance=a) 
    if request.method == "POST": 
     formset = bookformset(request.POST, request.FILES, instance=a) 
     if formset.is_valid(): 
      formset.save() 
     else: 
      form_errors = formset.errors 
      return render_to_response('test/authors_books_edits.html', {'author': a, 'authorsbooks': authorsbooks, 'formset': formset, 'form_errors': form_errors}, context_instance=RequestContext(request)) 
    return render_to_response('test/authors_books_edits.html', {'author': a, 'authorsbooks': authorsbooks, 'formset': formset,}, context_instance=RequestContext(request)) 

PLANTILLA

#all errors are here 
{% for dict in form_errors %} 
    {{ dict }} 
{% endfor %} 

#all forms are here, i want to pair the errors for each form 
<form method="post" action="/test/{{ author.id }}/books/"> 
    {% csrf_token %} 
     <table> 
     {{ formset }} 
     </table> 
    <input type="submit" value="Submit"/> 
    </form> 

plantilla actualizada: no muestra errores

<form method="post" action="/test/{{ author.id }}/books/"> 
    {% formset.management_form %} 
    {% csrf_token %} 
    <table> 
     {% for x in formset %} 
     {{x.errors }} 
     {{ x }} 
     {% endfor %} 
    </table> 
<input type="submit" value="Submit"/> 

Answer 1

EDITAR

authors_books_edits.html

<form method="post" action="/test/{{ author.id }}/books/"> 
    {% csrf_token %} 
    {{ formset.management_form }} 
    {% for form in formset.forms %} 
     {{ form.non_field_errors }} 
     {{ form.errors }} 
     <table> 
      {{ form.as_table }} 
     </table> 
    {% endfor %} 
    <input type="submit" value="Submit"/> 
</form> 

views.py

from django.shortcuts import * 
from django.forms.models import inlineformset_factory 

from .models import * 

def author_books_edit(request, author_id): 
    a = get_object_or_404(Author, pk=author_id) 
    authorsbooks = a.books_set.all() 
    bookformset = inlineformset_factory(Author, Books, can_delete=True, can_order=True, exclude=('company',), extra=1) 
    formset = bookformset(instance=a) 
    if request.method == "POST": 
     formset = bookformset(request.POST, request.FILES, instance=a) 
     if formset.is_valid(): 
      formset.save() 
     else: 
      form_errors = formset.errors 
      return render_to_response('authors_books_edits.html', {'author': a, 'authorsbooks': authorsbooks, 'formset': formset, 'form_errors': form_errors}, context_instance=RequestContext(request)) 
    return render_to_response('authors_books_edits.html', {'author': a, 'authorsbooks': authorsbooks, 'formset': formset,}, context_instance=RequestContext(request)) 

models.py

from django.db import models 

class Author(models.Model): 
    fname = models.CharField(max_length=100) 
    lname = models.CharField(max_length=100) 
    def fullname(self): 
     return '%s %s' % (self.fname, self.lname) 
    fullname = property(fullname) 
    def __unicode__(self): 
     return self.fullname 

class Books(models.Model): 
    author = models.ForeignKey(Author) 
    title = models.CharField(max_length=50) 
    publisher = models.CharField(max_length=50) 
    edition = models.CharField(max_length=50) 
    comment = models.TextField() 
    def __unicode__(self): 
     return self.title 

urls.py

from django.conf.urls.defaults import patterns, include, url 

urlpatterns = patterns('testapp.views', 
    url(r'test/(?P<author_id>\d+)/books/$', 'author_books_edit'), 
) 

Usted puede hacer otra aplicación temporal para probarlo.

Parece que este: http://imageshack.us/photo/my-images/824/screenshotat20120227190.png/

END == EDITAR

Usted puede iterar sobre las formas como tal:

{% for form in formset.forms %} 
    {{ form }} 
{% endfor %} 

En ese caso, consulte el Django de mostrar un formulario utilizando una plantilla documentación: https://docs.djangoproject.com/en/dev/topics/forms/#displaying-a-form-using-a-template

Entonces, más interesante, personalizando una plantilla de formulario (vea form.non_field_errors): https://docs.djangoproject.com/en/dev/topics/forms/#customizing-the-form-template

Answer 2

Suponiendo que el libro es una forma que podría hacer:

{% for b in authorsbooks %} 
    {{b.errors}} 
{% endfor %}